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x^2=12100
We move all terms to the left:
x^2-(12100)=0
a = 1; b = 0; c = -12100;
Δ = b2-4ac
Δ = 02-4·1·(-12100)
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{48400}=220$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-220}{2*1}=\frac{-220}{2} =-110 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+220}{2*1}=\frac{220}{2} =110 $
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